Hi
i need to create a Report from XML file which available in my current folder.
can anybody suggest How to create a Data source from XML file and How to make a query for that.
Thanks
Mahesh
Are you doing this in an application with ReportViewer in LocalMode? Or is this going to be a server-side app (where you're just using the XML file in your folder as a test file)?
The way to do it is different, depending on the answer to this first question... but in both cases I will have the followup question:
Is the XML file in a regular, table-like format (like Dataset XML), so that it will be easy to make into a datasource? Or is the schema different altogether?
>L<
|||Hi thanks for ur reply
now we have chenged the way i need to prepare a report
One web service will return a DataSet
based on that Dataset i need prepare a report.
Thanks
Mahesh
|||hi Mahesh,
That change doesn't really change anything about my first question, although it answers the second one<g>.
The way you are going to do this is still going to be different depending on whether the report is rendered server-side or client-side. Are you writing a web-application, a win-forms application, or what? Are you using the reportviewer client control?
If you need to send that dataset as a source to a server-side rendering of the report, you are still going to have to send that information as XML to the server. (But that will be easy because the dataset will turn itself into the "right kind" of XML for this purpose.) If you need to do this, we will discuss further.
If you are rendering the report using reportviewer, so you can use local report mode, then you can almost certainly give the localmode report your dataset without any trouble, and without turning it into XML first. In fact, if you *are* using XML, you load it into a dataset to give to the viewer control <s>.
Hope this helps
>L<
|||Hi Lisa
Thanks for giving more information
I need to prepare a Server side Report .
with sql server 2005 we got One VS 2005 IDE in that i have taken Report Server Project Here am creating my reports.
for this they are given me a webservice link that will return a Data set
based on that i need to prepare a Report.
Previously i know how to prepare a report from Sql server Database.
Thanks.
Mahesh
|||OK. If the webservice returns a dataset, then it returns it as an XML message. You should be fine with this in a server-side report.
Define the datasource as follows:
The DataSource is of type XML.The connection string for the web service datasource is in fact the URL for the web service! (http://...) For testing you can put up a local copy of it (http://localhost/test/my.xml) and assign that as your datasource.
The query string, believe it or not, can just be "*". (no quotes) if the XML is a "raw" dataset style. You can also use the (bleh) element query syntax that they've specified -- see here http://technet.microsoft.com/en-us/library/ms365158.aspx -- If you get stuck, post an example of what the web service response message looks like and I'll try to help.|||
Hi
Lisa
i was struck with writing query
i got the webservice responce
<?xml version="1.0" encoding="utf-8" ?>
- <DataSet xmlns="http://tempuri.org/">
- <xschema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn
chemas-microsoft-com:xml-msdata">
- <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
- <xs:complexType>
- <xs:choice minOccurs="0" maxOccurs="unbounded">
- <xs:element name="Project">
- <xs:complexType>
- <xsequence>
<xs:element name="ProjectUID" msdataataType="System.Guid, mscorlib, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089" type="xs
tring" minOccurs="0" />
<xs:element name="ProjectName" type="xstring" minOccurs="0" />
</xsequence>
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xschema>
- <diffgriffgram xmlns:msdata="urn
chemas-microsoft-com:xml-msdata" xmlns
iffgr="urn
chemas-microsoft-com:xml-diffgram-v1">
- <NewDataSet xmlns="">
- <Project diffgr:id="Project1" msdata:rowOrder="0">
<ProjectUID>8f584354-259b-48fb-a82b-838dd0d75a52</ProjectUID>
<ProjectName>Reports</ProjectName>
</Project>
</NewDataSet>
</diffgriffgram>
</DataSet>
In DataSet dialog Box i have taken a query
first i tried with "*" only it is showing error
an tried with this
<Query>
<SoapAction>
http://tempuri.org/GetAttributes
</SoapAction>
<Method Namespace="http://tempuri.org/"
Name="GetAttributes">
</Method>
</Query>
It is also not displaying the values of ProjectUid and ProjectName.
can u help me how to write the query for this type of WebService Responce.
Thanks
Mahesh
|||Mahesh, I thought they were sending you a dataset -- is the method GetAttributes the way you are supposed to get that dataset or does it represent a query you are trying to do to get the metadata *describing* the dataset?
Either way... To use the dataset "raw", the thing you are receiving should look like, well, a serialized dataset, like you would get from a dataset if you used its .WriteXML() or .GetXML() methods. You can't use the "*" (I don't think) unless it looks like that. I can't remember what MS blog I read about this in -- it works, but it is only the simplest way.
It is not the only way. Here is a very quick walkthrough that you should find helpful for your scenario: http://blogs.msdn.com/bimusings/archive/2006/03/24/560026.aspx
Here is another walkthrough http://msdn.technetweb3.orcsweb.com/gsnowman/archive/2005/10/12/480321.aspx
And a blog entry that goes through it again http://blogs.msdn.com/bwelcker/archive/2005/11/13/492296.aspx
I think they both show you examples of query syntax.
Here is a tutorial about using XML as a datasource that will help you -- I'm pointing you at lesson 2, where you're learning how the web service is supposed to return the serialized data set but you probably want to look at all the lessons in this tutorial -- http://technet.microsoft.com/en-us/library/aa337489.aspx
Other references describing other aspects that I have found helpful.
http://technet.microsoft.com/en-us/library/aa964129.aspx
http://channel9.msdn.com/ShowPost.aspx?PostID=137650
>L<
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